\u4eca\u5929\u95f2\u6765\u65e0\u804a\uff0c\u5199\u4e86\u4e00\u4e2a\u5c06\u5341\u8fdb\u5236\u8f6c\u6362\u4e3a\u4e8c\u8fdb\u5236\u7684\u5c0f\u7a0b\u5e8f\uff0c\u53ea\u7528\u4e8e\u6b63\u6570\u3002
\u5728GCC4.0\u4e0b\u6d4b\u8bd5\u901a\u8fc7\uff0c\u4ee3\u7801\u5982\u4e0b\uff1a
====================================================================
#include<stdio.h>
#include<stdlib.h>
main(int argc,char* argv[])
{
int YuShu[300],Bin[300],i=0,Dec;
int YuShuCount=0,BinCount=0;
if (argc != 2)
{
printf("Usage:dtb number(decimal number)n");
return 1;
}
Dec=atoi(argv[1]);
if (Dec == 1 )
{
printf("The Binary number is:1n");
return 0;
}
while (1)
{<\/p>\n
if (Dec >= 2)
{
YuShu[YuShuCount]=Dec % 2;
Dec = Dec \/ 2;
YuShuCount++;
}
else
{
YuShu[YuShuCount]=Dec;
for (i=0;i<=YuShuCount;)
{
Bin[BinCount]=YuShu[YuShuCount];
YuShuCount–;
BinCount++;
}
printf("The binary number is:");
for (i=0;i<BinCount;i++)
{
printf("%d",Bin[i]);
}
printf("n");
return 0;
}
}<\/p>\n